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Welcome to GCSE Edexcel Science revision.

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Unit S P 2: Motion and forces.

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The resultant force is the overall force on one object after all its forces are combined, taking account of their directions (their vector sum).

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Choose positive and negative directions consistently.

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A 1000 newtons driving force forward and 500 newtons drag backward give a resultant of 500 newtons forward.

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Subtract opposing forces; retain the direction of the larger force.

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Balanced forces give zero resultant and no acceleration.

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A stationary object stays stationary; a moving object continues at constant velocity.

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Newton’s first law describes this behaviour in the absence of a resultant external force.

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Motion does not require a continuing resultant force.

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Unbalanced forces cause acceleration: a change in speed, direction or both.

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A moving object can slow down if the resultant opposes its velocity.

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Circular motion at constant speed requires a resultant force towards the centre.

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This centripetal force changes the direction of velocity, so the object accelerates.

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Mass describes how much matter an object contains and is measured in kilograms.

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It also measures how difficult it is to change the object’s velocity (inertia).

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Weight is the gravitational force on the object, measured in newtons.

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Weight equals mass times gravitational field strength, W equals M times G.

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Near Earth use G equals 10 newtons per kilogram in these examples or the value given.

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A 6 kilograms object weighs 60 newtons where G equals 10 newtons per kilogram.

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Its mass stays 6 kilograms on the Moon, but its weight is smaller because the gravitational field is weaker.

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Measure weight with a calibrated newton meter.

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On a weight, mass graph, the gradient is gravitational field strength.

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Air or water resistance (drag) opposes an object’s movement relative to the fluid around it.

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Drag generally increases with speed.

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Streamlining reduces it.

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A falling object initially accelerates because weight exceeds drag.

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As speed increases, drag increases and the resultant becomes smaller.

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At terminal velocity, drag balances weight and acceleration is zero.

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The object continues falling at constant velocity; the forces have not disappeared.

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At terminal velocity, resultant force is zero.

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Opening a parachute increases drag: the falling person slows until reaching a new, lower terminal velocity.

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Newton’s second law is F equals M times A: resultant force in newtons equals mass in kilograms times acceleration in metres per second squared.

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For the same mass, increasing resultant force increases acceleration.

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For the same resultant force, a larger mass has a smaller acceleration.

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Inertial mass equals F divided by A.

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It measures how strongly an object resists a change in velocity.

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In the trolley core practical, vary pulling force while keeping total moving mass constant, or vary mass while keeping force constant.

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Use light gates or a motion sensor to calculate acceleration.

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Keep track and release conditions consistent, minimise friction and repeat measurements.

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A hanging mass and pulley can provide a pulling force; the hanging mass belongs to the moving system.

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Newton’s third law: when two objects interact, each exerts an equal and opposite force of the same type on the other.

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A foot pushes a ball forward; the ball pushes the foot backward.

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These forces act on different objects and do not balance each other on the ball.

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A book’s weight and the table’s upward normal force can balance on the book.

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They are not a third-law pair: the partner to Earth pulling the book is the book pulling Earth.

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Balanced forces on the book are not a Newton’s third-law pair.

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Momentum equals mass times velocity, P equals M times V, in kilogram metres per second.

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Momentum is a vector, so direction matters.

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Total momentum is conserved in a closed system with no resultant external force: add the momenta of all objects before and after a collision, using signed velocities.

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A 2 kilograms trolley at 3 metres per second hits a stationary 1 kilogram trolley and they stick together.

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Initial momentum is 6 kilogram metres per second; final combined mass is 3 kilograms, so final velocity is 2 metres per second.

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Negligible external resultant force allows momentum conservation.

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Average resultant force equals change in momentum divided by time, F equals the quantity M times V minus M times U, divided by T for constant mass.

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Use the sign of the velocity change.

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For the same change in momentum, increasing stopping time reduces average force.

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Crumple zones, airbags and seat belts extend stopping time and reduce injury risk.

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Momentum conservation does not mean kinetic energy is always conserved.

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In a sticking collision, some kinetic energy is transferred to other stores.

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Stopping distance equals thinking distance plus braking distance.

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Thinking distance is how far a vehicle travels before the driver starts braking.

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A delay before braking adds to the distance travelled.

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Thinking distance equals speed times reaction time, assuming speed stays constant during the reaction interval.

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At 20 metres per second and 0.5 seconds, it is 10 metres.

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Reaction time varies between people and conditions; drugs, alcohol, tiredness and distractions can increase it.

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A simple ruler-drop test can investigate reaction time with repeats.

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Braking distance depends on speed, mass, braking force, tyre condition, brake condition and road surface.

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Wet or icy roads reduce available friction.

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Higher speed increases thinking distance and increases braking distance more strongly.

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With fixed braking force, braking distance is proportional to speed squared.

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Large decelerations require large forces and can cause injury.

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Safety features reduce force by increasing collision time, but do not remove the momentum change.

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Braking transfers the vehicle’s kinetic energy into thermal energy in brakes, tyres, road and surroundings.

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With an approximately constant braking force, work done F times D equals initial kinetic energy one half times M times V squared.

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Rearrange to braking distance d equals mass times initial speed squared divided by the quantity two times braking force.

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If mass and braking force stay unchanged, braking distance is proportional to the square of initial speed: doubling speed gives four times the braking distance.

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The curve follows relative braking distance equals relative initial speed squared; the axes use relative quantities.

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Thinking distance equals speed times reaction time.

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With the same reaction time, doubling speed doubles thinking distance.

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Stopping distance adds thinking and braking distances.

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It does not exactly follow speed squared, because only the braking part does in this model.

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For a 1000 kilograms car travelling at 20 metres per second with 5000 newtons braking force, kinetic energy is 200000 joules and braking distance is 40 metres.

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With reaction time 0.7 seconds, thinking distance is 14 metres and total stopping distance is 54 metres.

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Use a realistic speed range to estimate emergency stopping distances and state assumptions.

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Wet or icy roads can reduce available braking force and lengthen braking distance; vehicle condition and driver response also matter.

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In this model, increasing mass with an unchanged braking force increases braking distance.

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In real vehicles the available force can also change with mass, so distinguish the specified calculation model from a universal rule.

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That completes Motion and forces.

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Revisit the notes and test yourself on the revision website.
